Algebra 2 help/medal

Question

anonymous · Answer

attachment

anonymous · Answer

I only got -1 :/

anonymous · Answer

Can you help me @Loser66 im confused on this

loser66 · Answer

nope, -1 is not one of the solution

anonymous · Answer

it isn't?

loser66 · Answer

try -2, and then using either long division or synthetic to find other two answers

anonymous · Answer

but -2 isn't a choice? if I can do the opposite sign then its -2, 3, -4 but I didn't think I could use them

loser66 · Answer

ok, if -1 is one of the solution, now, test
$$(-1)^3 +3*(-1)^2-10*(-1)-24=-1+3+10-24=-12\neq 0$$

loser66 · Answer

why not? -2 is a choice , because if it is a solution, then (x -(-2)) = (x+2 ) is one of the factors

loser66 · Answer

got me?

anonymous · Answer

am I allowed to use the opposite sign?

anonymous · Answer

ohhhhhhhhh ok yes I see. so its all the opposite... 1, -2, 3, -4, -6, and 12?

loser66 · Answer

@Mr.Expensive ,hihihi, let me, Mr. Cheap, show you the rule
if -2,3,-4 are solution of the expression, then (x+2)(x+3)(x-4) is factor form of the expression

loser66 · Answer

Nope, the expression has just 3 solutions. Not 1, -6 and 12

anonymous · Answer

ok yes I know it only has 3 im just saying all the options are opposite