Question

The equation of a circle whose center is at (4, 0) and radius is length 2√(3) is

Answer 1

Can anyone help me please ?

Answer 2

Do you have answer chioces to choose from

Answer 3

@Summi45618
(x - 4)² + y² = 2√3

(x - 4)² + y² = 12

(x + 4)² + y² = 12

Answer 4

Well it could not be c because of the (x +4 that needs to be (x-4

Answer 5

Ok so we know what the x and y axis are right.....SO x-axis is 4 and the y-axis is 0 Sp try to fill in the variable and tell me what answer you get

Answer 6

And which answer choice works for you

Answer 7

Is it "B"? @Summi45618

Answer 8

Um...Good Try but not quiet....Here I have an example let me show you

Answer 9

Use the standard equation for a circle of radius r with its centre at (p, q)
Then (x - p)² + (y - q)² = r²
Substituting the values given in the question - I've assumed the radius is meant to be 2√3 but if this is wrong the basic process is still the same.
(x - 4)² + (y - 0)² = [2√3]² = 12
(x - 4)² + y² = 12

The LHS can be expanded if required.
x² - 8x + 16 + y² = 12........and then simplified
x² - 8x + y² = -4

Answer 10

Does this example make sense?

Answer 11

I'm sorry. I am trying to break it down so I can apply it to the question I have but my program has a time thingie on it so I keep going back inbetween the two sites to make sure it doesnt timeout because it wont let me log back in. But im trying to understand :/ @Summi45618

Answer 12

OH OH IS IT A? @Summi45618

Answer 13

Correct!!!!!!!!!

Answer 14

YAYYYY THANK YOU ! Thats only number two out of 30 . Omg I suck @Summi45618

Answer 15

@DisCrazyGinger Thank you !!!!!