Running with an initial velocity of 10m/s, a horse has an average acceleration of -1.85m/s2. How long does it take for the horse to decrease its velocity to 6.9m/s ?
Use the following equation of motion:\[v_i + at = v_f\]Where the symbols are their usual meanings: \(v_i\) is the initial velocity. \(v_f\) is the final velocity. \(a\) is the average acceleration. \(t\) is the time.
So would I just insert all the given variables and get t by itself in order to find the time?? My physics prof. hasn't been super clear in his explaining so he leaves it up to us to figure out.
yes, fill in the info. what equation do you get ?
Follow phi. You know three of those quantities. You thus have one unknown quantity, \(t\).
(10m/s) + (-1.85m/s^2) t = 6.9m/s would be the equation
That's right. The unit of \(t\) is seconds, so you cancel that sec out with the sec in the denominator.
So then to the 10 m/s would get added to the 6.9m/s and then divide by -1.85??
add -10 to both sides
(10m/s) -10 m/s+ (-1.85m/s^2) t = 6.9m/s -10 m/s
Then I would add 1.85 to both sides correct??
no, you said it correctly the first time: and then divide by -1.85??
1.68 sound right?
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