The long diagonal of a kite is a perpendicular bisector to the short diagonal. Using this piece of information, how can you prove that adjacent sides are congruent in a kite?
@nailpolisheverywhere @OOOPS @aajugdar @Nurali
Label the four vertices of the kite as A, B, C, D going in clockwise direction, for example. Now we have two diagonals AC, and BD. Assuming AC is the long diagonal it intersects and bisects BD at a point, E , for example. Consider triangles AEB, and AED, angle AEB = angle AED = 90, because the two diagonals are perpendicular. And EB = ED because AC bisects BD. And third, AE is common between the two triangles. Therefore, the two triangles are congruent by side-angle-side. It follows that AB is congruent with AD. Thus the two adjacent sides are congruent. In a similar fashion, we can show that CB and CD are congruent. Using the results above we have also shown that angle BAE = DAE , therefore diagonal AC bisects angle DAB. And also, we have shown that angle BCE = DCE, therefore diagonal AC bisects angle DCB.
|dw:1402604764655:dw| this will help u get it
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perpendicular bisector divides a line in two equal parts,so DE =EB and 90* angle to both and a common side AE so by side angle side property the triangles are congruent so the adjacent sides AD and DB are congruent :)
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