Question

Need help proving the following

Answer 1

\[\frac{ \sin(x) }{ 1-\cos(x) }+ \frac{\sin(x) }{ 1+\cos(x) }=2\csc(x)\]

Answer 2

Combine the terms on the left hand side.

Answer 3

In the denominator, you will have a trig identity.

Answer 4

I have tried that and i knows you end up with \[\frac{ \sin(x)-\sin(x)\cos(x)+\sin(x)+\sin(x)\cos(x)}{ \sin^2(x)}\] which would be\[\frac{ 2\sin(x) }{ \sin^2(x) }\] simplified

Answer 5

i just don't know were to take it from there.

Answer 6

sin^2(x) = sin(x) * sin(x)

Answer 7

Does that help?

Answer 8

Yes, thank you.

Answer 9

Awesome. No problem.