what is the value of a1 for a geometric sequence with a4=40 and a6=160
a-2
b-5
c-8
d-10
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jimthompson5910 (jim_thompson5910):
Hints:
a5 = a4*r
a6 = a5*r ---> a6 = (a4*r)*r
jimthompson5910 (jim_thompson5910):
a6 = (a4*r)*r turns into a6 = a4*r^2
jimthompson5910 (jim_thompson5910):
because a6 = a4*r^2, a4=40 and a6=160, we can say
a6 = a4*r^2
160 = 40*r^2
r = ???
OpenStudy (anonymous):
What does r stand for
jimthompson5910 (jim_thompson5910):
r is the common ratio
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OpenStudy (anonymous):
duh
OpenStudy (anonymous):
so the common ratio is what?
jimthompson5910 (jim_thompson5910):
if you have the fourth term a4, you multiply that fourth term by r to get the fifth term
this applies in general to any term (not just the 4th term)
jimthompson5910 (jim_thompson5910):
here's an example of a geometric sequence
1, 2, 4, 8, 16, 32
Notice how each term is multiplied by 2 to get the next one (eg: 4 ---> 8, 8 = 4*2)
jimthompson5910 (jim_thompson5910):
so in my example, r = 2
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OpenStudy (anonymous):
Ok so the common ratio in my problem is 2?
jimthompson5910 (jim_thompson5910):
no, that's for my example
jimthompson5910 (jim_thompson5910):
I don't know what your common ratio r value is yet
OpenStudy (anonymous):
I know, i realized i made a mistake when i posted that one
jimthompson5910 (jim_thompson5910):
you have to solve 160 = 40*r^2
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OpenStudy (anonymous):
How do i find the common ratio for that
OpenStudy (anonymous):
nevermind
jimthompson5910 (jim_thompson5910):
Solving 160 = 40*r^2 gives you r = ???
OpenStudy (anonymous):
wouldnt it be 2?
jimthompson5910 (jim_thompson5910):
yeah it's actually 2
it's a coincidence that I used 2 as well
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OpenStudy (anonymous):
Ok thats what i thought haha
jimthompson5910 (jim_thompson5910):
Now we use the formula
\[\Large a_{n} = a*(r)^{n-1}\]
jimthompson5910 (jim_thompson5910):
plug in n = 4, r = 2 to get
\[\Large a_{n} = a*(r)^{n-1}\]
\[\Large a_{4} = a*(2)^{4-1}\]
Then plug in \(\large a_{4} = 40\) to get
\[\Large 40 = a*(2)^{4-1}\]
now solve for 'a'
OpenStudy (anonymous):
Ok now i can plug in one of a b c or d
OpenStudy (anonymous):
ok
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jimthompson5910 (jim_thompson5910):
you could, but solving is more direct
jimthompson5910 (jim_thompson5910):
I recommend doing it this way because you shouldn't be dependent on multiple choice. What if this was a free response or fill in the blank problem?
OpenStudy (anonymous):
Good point
jimthompson5910 (jim_thompson5910):
I guess though, having multiple choice there means you should take advantage of it to save time. So you should know how to do it both ways.
OpenStudy (anonymous):
So its b
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