Question

The function Q(t)=Qsub(o)e^-kt may be used to model radioactive decay. Q represents the quantity remaining after t years; k is the decay constant. What is the decay constant for plutonium-240 if its half-life is 6,300 years?

A.-[ln(0.5)/6,300]
B.ln(0.5)/ln(6,300)
C.240ln(0.5)/6,300
D.ln(0.5)/240

Answer 1

A is my reasoning correct lol or even the answer ?????
e^(-6300k) = 0.5
-6300k = ln(0.5)
k = ln(0.5) / (-6300)
k = -ln(0.5) / 6300

Answer 2

yes,

So it looks like A is our winner! :)