rewrite the following in standard form?

x^2+14x+44y+313=0

3y^2+6y+108x-969=0

x^2-12x-48y+372=0

Question

rewrite the following in standard form?

x^2+14x+44y+313=0  

3y^2+6y+108x-969=0 

x^2-12x-48y+372=0

anonymous · Answer

Do you know what is the standard form of a parabola?

anonymous · Answer

No, I'm really lost :(

anonymous · Answer

The standard form is 
y=ax^2 +bx +c

anonymous · Answer

Where a,b and c are real numbers. (any number)

anonymous · Answer

Ok, so could you just show me how to one of them  first as an example?

anonymous · Answer

x^2+14x+44y+313=0  
So I will help you with the above. 
44y has to be taken to the other side of the equation. Thus we subtract 44y from both sides.
x^2+14x+31=-44y

anonymous · Answer

Have to go for a while now

anonymous · Answer

Oh, so thats it?

anonymous · Answer

x^2+14x+31=-44y 
Just dived it by -44 to get the standard form. It will look ugly :)

anonymous · Answer

The goal is that the equation should look like y=something something something