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rewrite the following in standard form? x^2+14x+44y+313=0 3y^2+6y+108x-969=0 x^2-12x-48y+372=0
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Do you know what is the standard form of a parabola?
No, I'm really lost :(
The standard form is y=ax^2 +bx +c
Where a,b and c are real numbers. (any number)
Ok, so could you just show me how to one of them first as an example?
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x^2+14x+44y+313=0 So I will help you with the above. 44y has to be taken to the other side of the equation. Thus we subtract 44y from both sides. x^2+14x+31=-44y
Have to go for a while now
Oh, so thats it?
x^2+14x+31=-44y Just dived it by -44 to get the standard form. It will look ugly :)
The goal is that the equation should look like y=something something something
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