at sangers auto garage, 40% of the cars brought in for service need an oil change. of the cars that need oil change, 30% also need a tire rotation find the probability that a car that comes into the auto garage needs both an oil change and a tire rotation
3/10
If we let O = event that a car needs an oil change = 40% = 0.40 We will let (T|O) = event that a car needs a tire rotation, given that it has had a tire change already = 30% = 0.30 So we are looking for the probability that a car needs both or P(O 'intersection' T), then by conditional probability: \[P(O 'intersection' T) = P(O|T)P(T) = P(T|O)P(O)\] So, as P(T|O) = 0.30, P(O) = 0.40, this problem can be solved by multiplication.
We need both conditions, so multiply the probabilities. I would think the answer would be about .12 or 12 percent.
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