In CERN's intersecting Storage Ring, beam of protons of kinetic energy E eV (with a velocity approaching the velocity of light) carries I ampere current in the ring of circumference C meter.Then the total energy of the beam when it is ejected from the ring is? Please explain the steps
Jesus Christ! I didn't know there was another Particle Physicist here! I work at C.E.R.N too!
Want to get a beer after work, mate? I know this place just up the road.
Is this a serious question or?
The Intersecting Storage Ring is, of course, no longer in use. However, the ISR was composed of two interlaced rings with diameters of 150 metres. Each ring contained a beam pipe surrounded by magnets that directed the circulating particles. Protons circulated in opposite directions and collided with a maximum centre-of-mass energy of 62 GeV, equivalent to a 2000 GeV beam hitting a stationary target. The Proton Synchrotron, which is still in operation, fed proton beams into the ISR. They used this method because they knew that smashing two particle beams "head on" would give much higher collision energies that when a single beam of particles collides with a fixed target.
it is my homework question,so plz tell how to do this particular problem
Join our real-time social learning platform and learn together with your friends!