f(x) = -16x2 + 22x + 3 Part A: What are the x-intercepts of the graph of the f(x)? Show your work. (2 points) Part B: Is the vertex of the graph of f(x) going to be a maximum or minimum? What are the coordinates of the vertex? Justify your answers and show your work. (3 points) Part C: What are the steps you would use to graph f(x)? Justify that you can use the answers obtained in Part A and Part B to draw the graph. (5 points)
plz help
which part?
part b finding the vertex
you know that this graph represents a parabola?
yes but i dont know how to find the vertex without using a graph
for the vertex of the parabola, it has to reach a maxima or a minima. can you tell me what to do to find out the point where the graph reaches its maxima or minima?
no i donk know how to find that. ik that it is a minimum but thats it. is their a formula i can use
i think it is a maxima, but let's get there later. you know how to differenciate right?
i think maximum is downwards and has a positive leading coefficient and minimum is upwards and has a negative leading coefficient
i will help you with that later. at first tell me do you know how to differenciate?
no
okay, no problem. at first, let me be clear that this graph will attain maximum as it is downwards, because its co-efficient of leading term is negative
ok
when i graph it it look like its going upwards
now, for maximum, you need to find out where y=f(x)=-16 x^2+ 22x +3 attains maximum. -16x^2+22x+3=-(4x)^2+2*4x*2.75-(2.75)^2+3+(2.75)^2=10.5625-(4x-2.75)^2 with a little calculation you can reach this step.. tell me if you have understood
ok i get it
i just completed the square adjusted with 16x^2 and 22x
ok
nice! now as you can see, (4x-2.75)^2 is greater than or equal to zero always, so 10.5625-(4x-2.75)^2 will be maximum when 4x-2.75=0, or x=2.75/4 got it?
yes i got it
so, what is the maximum value of f(x)? obviously when 4x-2.75=0, that means x=0.6875 what is the value of f(x) at that point? clearly 10.5625 as you can see the function attains a maximum at (0.6875, 10.5625), it is the vertex
ohh ok so basically you find the maximum point?
yeah, maximum or minimum, depending on the co-efficient of the leading term. if it's positive, the graph is upward, f(x) is has minima, else the opposites
oh ok thank you so much can u help with part c now
this is what i put I would graph this equation by seeing what in formation i have. I already know the vertex and the points where it crosses the x axis. We also know that it is going to be an upwards parabola. I can plot all the points and make a rough drawing of how the parabola line would look.
no, this is downward parabola
oh ok is the rest good
everything else you have said are all correct :) good job!
ok thank you so much
you are welcome :)
Join our real-time social learning platform and learn together with your friends!