If a balloon is filled with helium and has a volume of 1.56 L @ 25 degrees C. What happens to the balloon if it is placed in a refrigerator at 4 degrees C? What is the amount that the VOLUME DECREASES??
Okay, so, the equation PV=nRT is what you're going to use to solve this. You're going to have to convert those liters into moles. Do you know how to do that?
To speed things along, the liter to mol conversion is 22.4 L to 1 mol. So convert your liters to mols by multiplying 1.56 L to 1 mol, then dividing by 22.4 L, you should come up with .069 mol.
Shoot, I thought there was a pressure value, nvm, back to step 1. Forget about the moles. Temperature and Volume are directly related, T= V, so actually convert your Celsius in to Kelvins. 25 C = 298.15 K 1.56 L = 298.15 X liters = 277.15 (the 4 C) So, set this up 1.56L/298.15 K = 277.15X
Calculating that, you'll find that the answer is 1.45 L. Does that help?
Ok, perfect. Thanks!
Np (:
The answer was actually 0.110 L :( but thanks!
Really? I have no idea what else would have been accounted for..
Me either. 1.45 L was one of the choices so I', knot sure
Oh wait, duh. It said the difference in the problem. You had to subtract the that volume from the initial.
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