Ask your own question, for FREE!
Chemistry 24 Online
OpenStudy (anonymous):

If a balloon is filled with helium and has a volume of 1.56 L @ 25 degrees C. What happens to the balloon if it is placed in a refrigerator at 4 degrees C? What is the amount that the VOLUME DECREASES??

OpenStudy (anonymous):

Okay, so, the equation PV=nRT is what you're going to use to solve this. You're going to have to convert those liters into moles. Do you know how to do that?

OpenStudy (anonymous):

To speed things along, the liter to mol conversion is 22.4 L to 1 mol. So convert your liters to mols by multiplying 1.56 L to 1 mol, then dividing by 22.4 L, you should come up with .069 mol.

OpenStudy (anonymous):

Shoot, I thought there was a pressure value, nvm, back to step 1. Forget about the moles. Temperature and Volume are directly related, T= V, so actually convert your Celsius in to Kelvins. 25 C = 298.15 K 1.56 L = 298.15 X liters = 277.15 (the 4 C) So, set this up 1.56L/298.15 K = 277.15X

OpenStudy (anonymous):

Calculating that, you'll find that the answer is 1.45 L. Does that help?

OpenStudy (anonymous):

Ok, perfect. Thanks!

OpenStudy (anonymous):

Np (:

OpenStudy (anonymous):

The answer was actually 0.110 L :( but thanks!

OpenStudy (anonymous):

Really? I have no idea what else would have been accounted for..

OpenStudy (anonymous):

Me either. 1.45 L was one of the choices so I', knot sure

OpenStudy (anonymous):

Oh wait, duh. It said the difference in the problem. You had to subtract the that volume from the initial.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!