Question

Multiply open parentheses 6 plus square root of 5 end root open parentheses 4 minus 2 square root of 5

Answer 1

help pls

Answer 2

Do you know how to expand expressions using the FOIL method?

Answer 3

no..

Answer 4

First Inner Outer Last
You multiply the first term in each bracket, multiply the inner terms of the two brackets (so sqrt(5) and 4), multiply the outer terms (6 and -2*sqrt(5)) and the last terms (sqrt(5) and -2*sqrt(5))
You add all these together and with a little bit of simplification you'll get the right answer. Remember to take the signs of each term into account

Answer 5

Basically:
(a+b)(c-d) = ac + bc - ad - bd

Answer 6

I got A, is that correct?

Answer 7

Nope, the correct answer is b

Answer 8

sqrt(5)*(-2*sqrt(5)) = -2*5 = -10

Answer 9

ooo yeah i see now thanks

Answer 10

mind helping me with a few more?

Answer 11

I can probably do that

Answer 12

i got D but idk if thats correct

Answer 13

When you multiply common bases (x) with exponents, you simply add the exponents together. For this one you just need to use a common denominator

Answer 14

so it's not D?

Answer 15

No it's C

Answer 16

oh so you have to keep the x/8 ?

Answer 17

I'm not sure what you mean.
1/4 = 2/8 so x^(1/4) * x^(5/8) = x^(2/8) * x^(5/8) = x^(7/8)

Answer 18

oo ok i see thanks

Answer 19

help me with these please

Answer 20

If you follow order of operations (Either PEMDAS or BEDMAS) you should get the answers to these

Answer 21

ok i got B for the first one?

Answer 22

You'll have to try that one again. To get rid of the square root you need to square both sides.

Answer 23

can u write that out for me?

Answer 24

\[\sqrt{(x-2) } = -4\]
\[(x-2) = (-4)^2 \]
\[x-2 = 16\]
\[x = 18\]