Question

If 4.0 moles of X and 4.0 moles of Y react according to the hypothetical reaction below, how many moles of the excess reactant will be left over at the end of the reaction?

2 X + 3 Y “yields”/ X2Y3

1.3 mol Y left over

2.7 mol Y left over

1.3 mol X left over

2.7 mol X left over

Answer 1

@aaronq

Answer 2

@iPwnBunnies

Answer 3

they give u the moles of the starting material. to do this u need to convert them both separately into the end products using mole/mole fractions based on the equation. the one with the smaller amount when both are converted to the end products is the limiting reagent and the other one is the excess

Answer 4

Do you think it's B?

Answer 5

I mean A, sorry **

Answer 6

4 mol Y * 1mol X2Y3 / 3 mol Y

Answer 7

=1.3Y

Answer 8

4mol X* 1 mol X2Y3/ 2 mol X= 2 mol X