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assign oxidation number to each atom is HSO3
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|dw:1402741283680:dw|
Oxygen -6 Hydrogen:+1 Sulphur:+5
\(\boxed{\boxed{\boxed{\color{red}{\huge\heartsuit\boxed{H}}\color{green}{\boxed{E}}\color{green}{\small\boxed{L}}\color{green}{\boxed{L}}\color{blue}{\huge\boxed{O}}\color{blue}{\huge\heartsuit}}}}\) @dinisha
For oxygen oxidation no is always -2 except in OF2 where its +2
For H its +1
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Now since HSO3 is a neutral molecule 1+x-6 =0
where x is the oxidation state of S
So x= +5
thanks @Abmon98 n @Abhisar :)
\(\Huge\text{Anytime !}\) \(\huge\ddot\smile\)
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