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Chemistry 14 Online
OpenStudy (anonymous):

assign oxidation number to each atom is HSO3

OpenStudy (anonymous):

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OpenStudy (abmon98):

Oxygen -6 Hydrogen:+1 Sulphur:+5

OpenStudy (abhisar):

\(\boxed{\boxed{\boxed{\color{red}{\huge\heartsuit\boxed{H}}\color{green}{\boxed{E}}\color{green}{\small\boxed{L}}\color{green}{\boxed{L}}\color{blue}{\huge\boxed{O}}\color{blue}{\huge\heartsuit}}}}\) @dinisha

OpenStudy (abhisar):

For oxygen oxidation no is always -2 except in OF2 where its +2

OpenStudy (abhisar):

For H its +1

OpenStudy (abhisar):

Now since HSO3 is a neutral molecule 1+x-6 =0

OpenStudy (abhisar):

where x is the oxidation state of S

OpenStudy (abhisar):

So x= +5

OpenStudy (anonymous):

thanks @Abmon98 n @Abhisar :)

OpenStudy (abhisar):

\(\Huge\text{Anytime !}\) \(\huge\ddot\smile\)

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