MEDAL WILL BE AWARDED!!! PLEASE HELP Find the mean absolute deviation for the following set of high temperatures recorded across the United States on August 21. {87, 72, 93, 91, 64, 86, 95}
@jim_thompson5910
What is the mean of this data set?
I got the mean of 84.
I seemed to do that step well, but then when it came to adding all the absolute values, the mean keeps on ending up as a decimal.
now subtract each value from the mean make those differences positive (so use absolute value)
okay, so maybe you may notice the mistake, if i did get one. 87-84=3 72-84=-8 93-84=9 91-84=7 64-84=-20 86-84=2 95-84=11 so i added the absolute values: 3+8+9+7+20+2+11=60 i am pretty sure that i got that one incorrect. @jim_thompson5910
72-84 should be -12 not -8
the answer is 12 right?
that's not the final answer
I'm just correcting part of your scratch work
wait, i am kind of confused in here. am i correct?
go back in how you subtracted in your work, you wrote "72-84=-8" when you *should* have this "72-84=-12"
yes that's what i did. then i added all the numbers up, and then divided it by 7 to get the mean, and got 12.
the answer is still not 12
so what's the next step?
you add up the absolute value differences (ie the distance each value is from the mean) then divide by 7
here's a page with an example http://www.mathsisfun.com/data/mean-deviation.html
i did and got the answer as 84, divided it by 7 = 12?
look over that page I posted
i am not getting this. so please can you tell me where i got my error?
please hurry up i have to go somewhere. ..
you have these distances: 3,12,9,7,20,2,11 average them to find your answer
so i add all of them and then divide it by 7?
please hurry ...
yes, add them up and divide by 7
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