Question

Medal and fan
If the solubility constant of silver iodide is 8.5x10^-17, what is the solubility of Ag^+?

Thankyou(:

Answer 1

2.9 * 10^-17

Answer 2

is any option like this ?

Answer 3

its similar to this

Answer 4

No. The options are: 9.2*10^-9, 4.0*10^-13, 2.0*10^-13, and 4.6*10^-9

Answer 5

idk this but it looks like A 9.2*10^-9

Answer 6

i got this by looking at my book

Answer 7

yes its 9.2*10^-9

Answer 8

Would you explain showing me how?

Answer 9

@seehearcreate look at the pic i posted and read it

Answer 10

im pretty sure u'll get it

Answer 11

Ksp = [Ag+][I-]

Answer 12

Same like u calculate Kc, the reactant hand side is a solid so take it 1

Answer 13

OHHH.

Answer 14

i don know why my first answer is always wrong, probably because i am so used to mcqs

Answer 15

:D

Answer 16

lol i think i should go through A level

Answer 17

but u gave the ryt answer @Somy

Answer 18

yeah i got it, i mean this is not something i learnt, i just looked up at A level part of my book, and it's there, so i understood how to do it

Answer 19

mine calculation was wrong :(

Answer 20

well that's okay, i was wrong in the previous question T_T

Answer 21

aaahh its all ryt, we r here for collective study...nobody can ryt all the time \(\color{green}{\huge\ddot\smile}\)

Answer 22

ikr :D

Answer 23

btw we took square root because ration between Ag and I was 1:1 @seehearcreate just in case saying

Answer 24

Nooo, I understood that lol

Answer 25

thats good :)