Given the function f(x)=x^3+x^2-2x+1, what is the resulting function when f(x) is shifted to the left one unit
simply replace each occurrence of `x` by `x+1`
Still trying to find a way to explain as simply as possible WHY that action would do the desired shift.. :D oh well ,never mind
So f(x+1)=(x+1)^3+(x+1)^2-2(x+1)+1?
bit tricky to explain - may be we need to go back in time and see how to fix the origin
As I said.. never mind. ^^
Excellent ! @Majestic4321 thats right !!
So then it would reduce to f(x-1)=x^3-2x^2-x+3?
\[f(x)=(x+1)^{3}+ (x+1)^{2}-2(x+1)+1\]
Right but that's not a choice so it would have to reduce right?
Is this the choice
feed it to wolfram : http://www.wolframalpha.com/input/?i=simplify+%28x%2B1%29%5E3%2B%28x%2B1%29%5E2-2%28x%2B1%29%2B1
No.name yes it is
then that is indeed the choice ,
Thank you:) I second guess myself a lot
no problem
hey no, wait a sec
What
` f(x-1)=x^3-2x^2-x+3` This is shift right transformation - Not the one the question was asking you to find
For left shift, ou need to find : f(x\(\color{Red}{+}\)1)
Oh... SO than it would be f(x+1)=x^3+4x^2+3x+1?
I think all of the choices are wrong... \(f(x + 1) = x^3 + 4x^2 + 3x + 1\) and \(f(x) = x^3 + x^2 - 2x + 1\) represent the same function. :P
yes they refer to the function f itself ! f(x+1)=x^3+4x^2+3x+1 is \(\large \color{red}{\checkmark}\) @Majestic4321
My options with positive one are f(x)+1=x^3+x^2-2x+2 or f(x+1)=x^3+4x^2+3x+1
Okay thanks haha
np, you seem new here... let me take a moment to welcome you :) \(\large \color{green}{\text{Welcome to Openstudy !}}\)
Yes I am thank you:)
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