Ask your own question, for FREE!
Chemistry 14 Online
OpenStudy (anonymous):

Consider the balanced equation. CuSO4 + Zn ------> ZnSO4 + Cu If 200.0 g of copper(II) sulfate react with an excess of zinc metal, what is the theoretical yield of copper? 1.253 g 50.72 g 79.63 g 194.3 g

OpenStudy (somy):

can u first find the mole of CuSO4?

OpenStudy (somy):

first thing for u to do is find mole of CuSO4 u have mass and u can find Mr from periodic table so find mole

OpenStudy (anonymous):

1.25 mols

OpenStudy (somy):

cool so now do u see that ratio between CuSO4 and Zn is same? 1:1

OpenStudy (somy):

BUT Zn is in excess so that means CuSO4 is limiting reagent right?

OpenStudy (anonymous):

so the answer is a? I have a bunch of quesitons i need help with can you help me somewhere

OpenStudy (anonymous):

i'm still confused

OpenStudy (somy):

no wait

OpenStudy (somy):

how did u find that its A?

OpenStudy (anonymous):

i got confused

OpenStudy (anonymous):

I need to know the answer I only have 2 more minutes to turn this in

OpenStudy (somy):

hhh look the ration between CuSO4 and Cu is 1:1 so means mole is same mass= mole * Mr

OpenStudy (somy):

1.25* 63=

OpenStudy (anonymous):

where do you get the 63 from

OpenStudy (somy):

1.25*63.5*

OpenStudy (somy):

63.5 is Mr of Cu

OpenStudy (somy):

u wanna find mass of Cu right?

OpenStudy (anonymous):

still kinda lost but thank you i have more problems can you help me with?

OpenStudy (somy):

lets see

OpenStudy (somy):

open new question for that

OpenStudy (anonymous):

kk

OpenStudy (somy):

i'll explain this after u are done with ur questions then ok?

OpenStudy (anonymous):

okay thank you

OpenStudy (anonymous):

i opened a new question

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!