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Simplify the given expression: 4 divided by the quantity of 3 minus 2i
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Btw this operating complex numbers, really need help thanks !
get rid of imaginary numbers in denominator by multiplying by conjugate \[\frac{4}{(3-2i)} *\frac{(3 + 2i)}{(3+2i)}\]
so now its 4/(3+2) ?
@dumbcow
you are getting the denominator correctly, but check your numerator.
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does it become negative? @SolomonZelman
Does `what become negative ?
16
nevermind
the numerator becomes 16 right?
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\[4(3+2i) =?\]
so 4(3) is 12 and 4(2i) is -8? so -4?
The denominator should be 3^2 + 2^2 = 13
I believe the final asnwer is 12-8i/13 is that correct>
And the numerator = 4*(3+2i) = 12+8i Final result is (12+8i) / 13
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Ok thanks alot I actually am starting to understand :)
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