Question

Medal and fan

The equilibrium reaction between chromate (CrO4^2-) and dichromate (CR2O7^2-) can be described by the following reaction:
2CrO4^2- + 2H^+ <-> Cr2O7^2- + H2O
yellow orange
The color of the solution can change depending on the species in excess.

The

Adding Ba(NO3)2 to the reaction causes CrO4^2- to precipitate. Describe how Ba(NO3)2 can be used to determine how much CrO4^2- is present, and then identify the color of the solution with a greater amount of precipitate.

Thanks(:

Answer 1

@Abhisar

Answer 2

sorry not sure about this one \(\color{green}{\huge\ddot\frown}\)

Answer 3

Hmmmm.

Answer 4

@rishavraj

Answer 5

@abb0t

Answer 6

@matt101 @aaronq @JFraser

Answer 7

@Somy

Answer 8

oh sorry i was off

Answer 9

No, that's fine. I think I actually figured it out when I was explaining precipitate formation to @rishavraj . The common ion Oxygen decreases k, and when q is more than k, a precipitate forms.

Answer 10

oh thats good then :)

Answer 11

just in case)

Answer 12

I think that would be correct. I think the precipitate would be yellow since k<1, which means equilibrium would favor the reactants, and the color of the chromate is yellow.

Answer 13

this is whats written in my book :) so yeah u r right :D

Answer 14

This has to do with the common ion principle plus k isn't given.

Answer 15

yeah but even if K is not given they are not asking u for it anyways, the principle is still same

Answer 16

Yupppp(:

Answer 17

they already told u that ppt WILL be formed so they already told u that K is less then [Ba2+][CrO4^2]

Answer 18

or whatever that it was

Answer 19

And since K is under 1 because of the common ion, it shifts towards the reactants.

Answer 20

lol i guess so
actually by telling u all these im learning side by side lmao

Answer 21

Hahaha, I've learned things that I didn't know either xD

Answer 22

lmao nice :D