I've got part A, can someone help me out?
-16t^2+50t+90 is the equation and answer to Part A.
Part B: What is the maximum height that the projectile will reach? Show your work.

Question

I've got part A, can someone help me out? 
-16t^2+50t+90 is the equation and answer to Part A.
Part B: What is the maximum height that the projectile will reach? Show your work.

cwrw238 · Answer

have you done any calculus 
finding derivatives?

anonymous · Answer

a little bit i guess

cwrw238 · Answer

you need to
 differentiate the above function and equate it to zero then solve for t

anonymous · Answer

i got 1.5625

cwrw238 · Answer

this will give you  the value of t when projectile is at maximum height
you then plug this into the original function of t

cwrw238 · Answer

-32t + 50 = 0
t = 50/32 = 1.5625

now plug this into -16t^2 + 50t + 90

anonymous · Answer

-16(1.5625)^2+50(1.5625)+90 = 129.0625 would that be correct?

cwrw238 · Answer

129.06?

cwrw238 · Answer

yes

anonymous · Answer

okay thank you! :)