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Mathematics 18 Online
OpenStudy (vera_ewing):

Find the value of e. http://curriculum.kcdistancelearning.com/courses/GEOMx-HS-A09/b/assessments/R-LawsofSinesandLawofCosinesQuiz/Geometry_8.4_Quiz_FINAL_8q.png

geerky42 (geerky42):

Because we are given the value of P, p, and E, we can use law of sines. \[\dfrac{\sin P}{p} = \dfrac{\sin E}{e}\]

OpenStudy (vera_ewing):

hmm...ok then what?

geerky42 (geerky42):

I hope this isn't from final quiz :)

OpenStudy (vera_ewing):

no it's not. it's from a take home test.

geerky42 (geerky42):

Well, solve for e? Plug in values, do little algebra.

OpenStudy (vera_ewing):

i don't know how :(

OpenStudy (vera_ewing):

@hba please. i'm so confused

OpenStudy (hba):

Plug them in vera and solve for e.

OpenStudy (vera_ewing):

plug what in?

OpenStudy (vera_ewing):

can you show me?

OpenStudy (hba):

The angles.

OpenStudy (hba):

and p

OpenStudy (vera_ewing):

sin(44)/17=sin(60)/e

OpenStudy (vera_ewing):

i have no idea what to do after that

OpenStudy (hba):

.-.

OpenStudy (vera_ewing):

i'm sorry. i'm confused about this concept.

geerky42 (geerky42):

no idea? You just need to isolate e. Seriously, if you are learning how to use law of sines, you should know basic algebra

geerky42 (geerky42):

So we have \(\dfrac{\sin(44^o)}{17} = \dfrac{\sin(60^o)}{e}\). Maybe we can do cross-multiply? We can try that.

OpenStudy (vera_ewing):

ok so sin(44)(e)=sin(60)/17

OpenStudy (vera_ewing):

sin(60)(17) ?

geerky42 (geerky42):

Yep that's right, now none are in denominator. that's better! But we need to isolate e. what to do with sin(44)?

OpenStudy (vera_ewing):

i'm not sure

geerky42 (geerky42):

maybe divide or something? what do you think?

OpenStudy (vera_ewing):

i guess we could could divide.

geerky42 (geerky42):

yeah. we divide both sides by what?

OpenStudy (vera_ewing):

44?

geerky42 (geerky42):

well, 44 is in sine function, you mean sin(44)?

OpenStudy (vera_ewing):

yes

geerky42 (geerky42):

okay, so we do that. \[e\cdot\sin(44) = 17\sin(60) \\ \dfrac{e ~ \cancel{\sin(44)}}{\cancel{\sin(44)}} = \dfrac{17\sin(60)}{\sin(44)} \\ e = \dfrac{17\sin(60)}{\sin(44)}\] Is this clear?

OpenStudy (vera_ewing):

we still have more simplifying to do? right?

OpenStudy (vera_ewing):

@geerky42 ?

geerky42 (geerky42):

well, you can solve sin(60), but for sin(44), you would need to use calculator. so pretty much you just calculate \(\dfrac{17\sin(60)}{\sin(44)}\)

geerky42 (geerky42):

What do you get?

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