Find the value of e. http://curriculum.kcdistancelearning.com/courses/GEOMx-HS-A09/b/assessments/R-LawsofSinesandLawofCosinesQuiz/Geometry_8.4_Quiz_FINAL_8q.png
Because we are given the value of P, p, and E, we can use law of sines. \[\dfrac{\sin P}{p} = \dfrac{\sin E}{e}\]
hmm...ok then what?
I hope this isn't from final quiz :)
no it's not. it's from a take home test.
Well, solve for e? Plug in values, do little algebra.
i don't know how :(
@hba please. i'm so confused
Plug them in vera and solve for e.
plug what in?
can you show me?
The angles.
and p
sin(44)/17=sin(60)/e
i have no idea what to do after that
.-.
i'm sorry. i'm confused about this concept.
no idea? You just need to isolate e. Seriously, if you are learning how to use law of sines, you should know basic algebra
So we have \(\dfrac{\sin(44^o)}{17} = \dfrac{\sin(60^o)}{e}\). Maybe we can do cross-multiply? We can try that.
ok so sin(44)(e)=sin(60)/17
sin(60)(17) ?
Yep that's right, now none are in denominator. that's better! But we need to isolate e. what to do with sin(44)?
i'm not sure
maybe divide or something? what do you think?
i guess we could could divide.
yeah. we divide both sides by what?
44?
well, 44 is in sine function, you mean sin(44)?
yes
okay, so we do that. \[e\cdot\sin(44) = 17\sin(60) \\ \dfrac{e ~ \cancel{\sin(44)}}{\cancel{\sin(44)}} = \dfrac{17\sin(60)}{\sin(44)} \\ e = \dfrac{17\sin(60)}{\sin(44)}\] Is this clear?
we still have more simplifying to do? right?
@geerky42 ?
well, you can solve sin(60), but for sin(44), you would need to use calculator. so pretty much you just calculate \(\dfrac{17\sin(60)}{\sin(44)}\)
What do you get?
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