Question

What is the 32nd term of the arithmetic sequence where a1 = -31 and a9 = -119? (1 points)

-372

-361

-350

-339

Answer 1

an=a1+(n-1)d => a9=a1+(9-1)d => 8d=a9-a1=-119-(-31)=-88 => d=-11.
then a32=a1+(32-1)d=-31+31*-11=-372. therefore a32=-372

Answer 2

Thank You So Much

Answer 3

no problem. any way, is it clear?

Answer 4

Yes Thanks