Question

factorise these polynominals
1. p(x)=4x-x^3 2. q(x)=2x^4 +12x^3-8x^2-48x Please Help due for tuesday :(

Answer 1

the 1st one... take x out as a common factor...

\[P(x) = x(4 - x^2) \]

you need to factor

\[4-x^2\]

which is the difference of 2 squares..

for question 2 group in pairs 1st

\[q(x) = (2x^4 -8x^2) + (12x^3 - 48x)\]

factor the brackets and you get

\[q(x) = 2x^2(x^2 - 4) + 12x(x^2 - 4)\]

which becomes

\[q(x) = (2x^2 + 12x)(x^2 - 4)\]

to finish you need to remove a common factor from

\[2x^2 + 12x\]

and factor

\[x^2 - 4\]

which is the difference of 2 squares

hope it helps

Answer 2

Also, \(\normalsize\color{midnightblue}{ (2x^2+12x) }\) can be factored out of \(\normalsize\color{midnightblue}{ 2x }\) to make the factorization complete.

Answer 3

thank you (:

Answer 4

number 2 i got q(x)= 2x(x+6) (x+2) (x-2)