Question

24^x-1=60

Answer 1

@ganeshie8

Answer 2

its suppose to be euqal to 59 not 60

Answer 3

i jsut have a question about logs

Answer 4

is it \(\normalsize\color{midnightblue}{ 24^x-1=59 }\) ?

Answer 5

yea thats the equation

Answer 6

add 1 to both sides and take log of both sides.

Answer 7

why do i have to pull out a 12 from 24^x=60

Answer 8

no you don't need to pull up 12 from 24, do what I told you to do first, please.

Answer 9

log60/log24?

Answer 10

yes

Answer 11

You can as well say,
\(\normalsize\color{midnightblue}{ log_{24}{60} }\)

Answer 12

ok and u get 1.2883 but an answer key i have says its suppose to be 2.32

Answer 13

and log5/log2 gets u that and u get log5/log2 by pulling out a 12

Answer 14

right?

Answer 15

@SolomonZelman

Answer 16

can u explain this to me :D

Answer 17

ikram002p?

Answer 18

If your question is \(\normalsize\color{midnightblue}{ 24^x-1=59 }\) , then

\(\normalsize\color{midnightblue}{ 24^x-1=59 }\)
\(\normalsize\color{midnightblue}{ 24^x=60 }\)
\(\normalsize\color{midnightblue}{ x~\log~24=\log 60 }\)
\(\normalsize\color{midnightblue}{ x=\log 60~/ \log~24 }\)

Answer 19

are you sure it is \(\normalsize\color{midnightblue}{ 24^x-1=59 }\) ?

Answer 20

its 59=4X3X2^x -1

Answer 21

its 59= 4*3*2^x -1

Answer 22

\[59=4\times3\times2^{x}-1\]

Answer 23

wait is it \(\normalsize\color{blue}{ 59= 4\times3\times2^x -1 }\) And 2 is the only that goes to the power of x ?

Answer 24

yes

Answer 25

\(\normalsize\color{blue}{ 59= 4\times3\times2^x -1 }\)
\(\normalsize\color{blue}{ 60= 4\times3\times2^x }\)
\(\normalsize\color{blue}{ 60= (12)\times2^x }\)
\(\normalsize\color{blue}{ 5=2^x }\) then you end up with log5/log2

Answer 26

oh wait can i not multiply 12 by 2^x?

Answer 27

yes i know that so am i not suppose to multiply \[12\times2^{x}=24^{x}\]

Answer 28

well, 12 times 2^x is just the result of simplifying

Answer 29

im jsut confused as to why u get a different answer depending if u divide by the 12 or if u dont

Answer 30

shouldnt it still be the same?

Answer 31

no I get different answer depending on whether it is \(\normalsize\color{red}{ \rm 59=4 \times 3\times 2^x-1 }\) or \(\normalsize\color{red}{ \rm 59=(4 \times 3\times 2)^x-1 }\)

Answer 32

See the difference ?

Answer 33

oh so if its the first one u wrote u are not suppose to multiply 12 and the 2^x?

Answer 34

well the 4,3 and 2^x