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Solve the equation 1/x-4 = x/ x^2-16
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Can you write the equation explicitly ..
What do you mean?
Is it\[\frac{ 1 }{ x-4 } = \frac{ x }{ x^2 - 16}\]
This is the problem
Yes
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Use x^2-16 = (x-4)*(x+4)
Would I then times x+4 to both sides?
Cross multiply and factorize.
Actually take (x-4) as common.
When I cross multiply I get (x-4)(x+4)=x^2-4 Is that correct?
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(x-4)(x+4)=x^2-4x
Make right hand side 0
Wait I just got confused
@ShailKumar (x-4)(x+4) = x^2-16
Manipulation of the equation gives: (x-4)(x+4)=x^2-4x
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