Question

(3x)^2+39-6x=

Answer 1

Final result :

3 • (3x^2 - 2x + 13)

Answer 2

\[3x ^{2}+39-6x\]

Answer 3

yes thats the problem

Answer 4

x =(2-√56)/2=1-√ 14 = -2.742
x =(2+√56)/2=1+√ 14 = 4.742

Answer 5

are you solving or factoring?

Answer 6

solving

Answer 7

Evaluate.

Answer 8

cant sorry

Answer 9

dont know how

Answer 10

Step by step solution :
Step 1 :

Simplify \[9x^2+39 - 6x\]

Pulling out like terms :

Pull out like factors :

\[9x^2 - 6x + 39 = 3 • (3x2 - 2x + 13) \]
Trying to factor by splitting the middle term

Factoring \[3x^2 - 2x + 13 \]

The first term is, \[3x^2\] its coefficient is 3.
The middle term is, -2x its coefficient is -2 .
The last term, "the constant", is +13

Step-1 : Multiply the coefficient of the first term by the constant 3 • 13 = 39

Step-2 : Find two factors of 39 whose sum equals the coefficient of the middle term, which is -2 .
-39 + -1 = -40
-13 + -3 = -16
-3 + -13 = -16
-1 + -39 = -40
1 + 39 = 40
3 + 13 = 16
13 + 3 = 16
39 + 1 = 40


Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Final result :

\[ 3 • (3x^2 - 2x + 13)\]

Answer 11

wow

Answer 12

thankss