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Mathematics 19 Online
OpenStudy (anonymous):

Class A Class B Class C 80 72 100 85 90 90 87 85 94 92 84 100 86 91 75 90 78 30 94 94 94 100 86 72 75 82 85 45 78 87 85 86 42 38 78 100 72 95 90 94 90 94 62 88 60 Question 1 Analyze the data for Class A and Class B. Part 1: What are the means and standard deviations for Classes A and B? Part 2: Make a box plot of the data for Classes A and B. Identify the median, first and third quartiles, and minimum and maximum data points. Part 3: Explain how the values for Classes A and B vary about the mean and median. What information does this give Mrs. Smith?

OpenStudy (anonymous):

The mean for class A is 79

OpenStudy (anonymous):

Remember, To find to mean, you just add all the numbers together, and then you divide the sum of those numbers, by the number of integers you have.

OpenStudy (anonymous):

?

OpenStudy (anonymous):

80 + 85 + 87 + 92 + 86 + 90 + 94 + 100 + 75 + 45 + 85 + 38 + 72 + 94 + 62 = ____

OpenStudy (anonymous):

I want you to add those numbers together and tell me what you get

OpenStudy (anonymous):

OK

OpenStudy (anonymous):

1,185

OpenStudy (anonymous):

great! now we need to divide, how many numbers do we have here? 80, 85, 87, 92, 86, 90, 94, 100, 75, 45, 85, 38, 72, 94, 62

OpenStudy (anonymous):

? what does that mean ? and thanks for all you help

OpenStudy (anonymous):

so i divide by 15 ?

OpenStudy (anonymous):

okay, we have 15 numbers here..

OpenStudy (anonymous):

so now, to find the mean, we will need to divide 1,185 by 15

OpenStudy (anonymous):

79

OpenStudy (anonymous):

there you go! 79 is the mean

OpenStudy (anonymous):

but now you need to find the mean for class B

OpenStudy (anonymous):

ok ik how do that know what about what about part 2 and many thanks i love you men not even my teacher makes it that easy

OpenStudy (anonymous):

Box plot, hmm, thats a bit hard for me to do, one second let me try to bring someone else in here

OpenStudy (anonymous):

@ganeshie8 @Hero @ParthKohli

OpenStudy (anonymous):

omg thank men your the best thanks for teaching me and not just giving me the answer

OpenStudy (anonymous):

Lol your welcome, and btw im a girl :)

OpenStudy (anonymous):

one moment, somebody should be coming to help out

OpenStudy (anonymous):

what ever i still love you lol hey i gat 85.133333 for b ? far part 1 ?

OpenStudy (anonymous):

um, one second let me see if that is correct

OpenStudy (anonymous):

You are correct, now you just turn it to 85.13

OpenStudy (anonymous):

79 - Class A 85.13 - Class B That's it for part 1

OpenStudy (anonymous):

I am going to bring somebody in so I can better assist you, one minute

OpenStudy (anonymous):

@phi @ParthKohli @jigglypuff314 @KingGeorge

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

@mathmale

OpenStudy (anonymous):

Part 2? need to make a box plot..

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

i never learned box plots either, so idk how to do part 2,

OpenStudy (anonymous):

how bout you ask some of the people you are fans of for help?

OpenStudy (anonymous):

@SolomonZelman

OpenStudy (anonymous):

i asked :/

OpenStudy (anonymous):

i am asking a bunch of people who are online and not one of them came, lol

OpenStudy (anonymous):

did you get how to work out the standard deviation for each column?

OpenStudy (anonymous):

are you allowed to use a spreadsheet or calculator? or do you have to show the working out?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

@SolomonZelman

OpenStudy (anonymous):

btw im home and i just need help in a only class

OpenStudy (anonymous):

help not answers

OpenStudy (anonymous):

its a bit of a pain to calculate standard deviations.. you can either put all the numbers into a spreadsheet, and then ask it to calculate it for you.. or you do it manually.. you have to subtract the mean from every value one at a time.. and then you take each result and square it..

OpenStudy (anonymous):

honestly i just need help :/

OpenStudy (anonymous):

then you add them all up.. and divide by either (the count of all the results) or (the count of all results - 1) just like you calculated the mean.

OpenStudy (anonymous):

i dont know here you gat -1 from

OpenStudy (anonymous):

you then take the square root of that value. and that is the standard deviation.. why would you use (the count of all the results -1) OR just (the count of all the results)?

OpenStudy (anonymous):

good thing you asked :) 1 sec.. explanation ...

OpenStudy (anonymous):

There are two main ways to calculate standard deviation: population standard deviation and sample standard deviation. Population : This is the equation for population standard deviation, which is used when all values of a population are known. Sample: This is the equation when only SOME of the values of a population are known.

OpenStudy (anonymous):

English plz lol

OpenStudy (anonymous):

if using sample equation.. then we add -1 Let's just forget -1 ... and say we have population formula.. and assume that all data points are known.

OpenStudy (anonymous):

sorry to confuse.. but you will likely run into this

OpenStudy (anonymous):

its ok thanks

OpenStudy (anonymous):

so subtract the mean from every number. square each result add all the results together divide by the count of the total number of results take the square root of that result you now have the standard deviation

OpenStudy (anonymous):

I would use a spreadsheet for this stuff.. like google spreadsheet under google Drive and Apps.

OpenStudy (anonymous):

you just enter all the values.. and then use the =stdev(RANGE) function

OpenStudy (anonymous):

purple math might help explain the box and whisker plot.. and using a spreadsheet will make it easy to order the values.. you just tell it to sort.. http://www.purplemath.com/modules/boxwhisk.htm

OpenStudy (anonymous):

do you have any experience with spreadsheets? They're really good at operating on a range of data.. you can lay data out on a table, and select whole ranges and operate on them.. for example to get the mean you can just enter into a cell "=average(a1:a5) and it would return the mean average of the cells labelled a1 to a5... its worth playing around with one for these types of problems.

OpenStudy (anonymous):

um let me try

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