Question

How many liters of fluorine gas, at standard temperature and pressure, will react with 23.5 grams of potassium metal? Show all of the work used to solve this problem.
2 K + F2--->2 KF

Answer 1

number of mole of potassium=23.5/39.1
0.60 moles of potassium
ratio of potassium to fluorine is 2:1
so 0.60 is halved so we get 0.30 moles of fluorine
under standard condition fluorine occupies a volume of 24dm^3
0.30*24=7.2dm^3