Two 26.0mLmL samples, one 0.100 M HCl and the other 0.100 M HF, were titrated with 0.200 MKOH. What is the volume of added base at the equivalence point for HCl?

Question

abmon98 · Answer

26.0 ml is 0.026dm^3 
number of moles of HCL is 0.026*0.100=0.0026moles
Construct a balanced Equation 
HCl+KOH-->KCl+H2O
Ratio of HCL to KOH is 1:1 so they share the same number of moles
number of moles=concentration*volume
0.0026=0.200*Volume
Volume=0.013dm^3
If you would like to convert into ml multiply the volume by 1000