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Chemistry 14 Online
OpenStudy (anonymous):

Two 26.0mLmL samples, one 0.100 M HCl and the other 0.100 M HF, were titrated with 0.200 MKOH. What is the volume of added base at the equivalence point for HCl?

OpenStudy (abmon98):

26.0 ml is 0.026dm^3 number of moles of HCL is 0.026*0.100=0.0026moles Construct a balanced Equation HCl+KOH-->KCl+H2O Ratio of HCL to KOH is 1:1 so they share the same number of moles number of moles=concentration*volume 0.0026=0.200*Volume Volume=0.013dm^3 If you would like to convert into ml multiply the volume by 1000

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