Power System : Fundamentals
Let voltage be \[v(t)=V_m cos(\omega t+\theta_v)\] Let the current be \[i(t)=I_m cos(\omega t+\theta_i)\] Power would be multiplication of the two \[p(t)=v(t)*i(t)=V_m cos(\omega t+\theta_v)*I_m cos(\omega t+\theta_i) \]
\[1/2 *V_m*I_m[cos(\theta_v-\theta_i)+cos2(\omega*t+\theta_v)*cos(\theta_v-\theta_i)+ \] \[sin2(\omega*t+\theta_v)*sin(\theta_v-\theta_i)\]
now using RMS value \[|V||I|*cos(\theta)(1+cos2(\omega*t+\theta_v)+|V||I|sin\theta*sin(\omega*t+\theta_v)\] \[\theta\] is \[\theta_v-\theta_i\]
now the two term above represent the fundamental of power system
\[|V||I|*cos(\theta)(1+cos2(\omega*t+\theta_v)\] is called real power, it is the power consumed by resistive load. There are three fundamental type of load( resistive , inductive, capacitive) .
The real power can be further classified, \[|V||I|*cos(\theta)(1+cos2(\omega*t+\theta_v)\] If you distribute it out , you will get two term the first term \[|V||I|*cos(\theta)\] is average power delivered to the load. which furthur , \[|V||I|\] is called apparent power usally denoted as \[S\] and \[cos \theta \] is power factor
now let's move on to second component of original power equation \[|V||I|sin\theta*sin(\omega*t+\theta_v)\] This is called reactive power, associated with inductive and capacitive component of load In this case our amplitude of reactive power is given by \[|V||I|sin\theta\].
which is denoted by Q
Another notation I like to introduce is complex power \[S=P+jQ\] S=Sqrt[P^2+Q^2]
//in progess, need to add more
Next , we will study Unit System
awesome tutorial ^_^ one thing to mention :) (1) aparent power is also called PHANTOM or FICTICIOUS power this type of power is mainly consumed by ac machines like transformers that is why ratiing of a transformer is in KVA (2) and true or real power is consumed by machines like IM(induction motors) and it gives their rating in KW
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