Question

Use the substitution method to solve the following system of equations.

9x + y = 0
18x + 4y = -8

Answer 1

how would you solve it? explain please

Answer 2

rewrite the first one as
\[y=-9x\] and then replace \(y\) in the second equation with \(-9x\) and solve
\[18x+4\times (-9x)=-8\] for \(x\)

Answer 3

18x+-36x=-8

Answer 4

@satellite73

Answer 5

x=4/9?
@satellite73

Answer 6

i don't know, i didn't do it
\[-18x=-8\]
\[x=\frac{8}{18}=\frac{4}{9}\] yeah looks good

Answer 7

how do i solve for y
@satellite73

Answer 8

i will let you do that on your own
hint:
\[9x+y=0\] and \[x=\frac{4}{9}\]

Answer 9

plug in the x , but then what @satellite73