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Mathematics 11 Online
OpenStudy (anonymous):

differentiate: S(p) = sqaureroot of P - P

OpenStudy (anonymous):

S(p) =[\sqrt{P}\]-P

OpenStudy (dan815):

1/2(p)^(-1/2)+1

OpenStudy (anonymous):

UHHHHHHHHH

OpenStudy (ikram002p):

\( \sqrt{P} -p\) ?

OpenStudy (anonymous):

yes

OpenStudy (ikram002p):

dan its -1 sweet heart <3

OpenStudy (ikram002p):

ok so wanna step by step ?

OpenStudy (ikram002p):

u can rewrite it like this \(p^{\frac{1}{2}}-p\)

OpenStudy (anonymous):

right

OpenStudy (anonymous):

then 1/2(p)(^1/2-1)

OpenStudy (ikram002p):

yes ur correct about \((\sqrt p)'\) dnt forget u have also -p

OpenStudy (anonymous):

but the p will 0?

OpenStudy (ikram002p):

nope p is not constant right ?

OpenStudy (anonymous):

right?

OpenStudy (ikram002p):

like this \(S(x) = \sqrt x - x\)

OpenStudy (perl):

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