please help...im desperate Choose the point which is a solution to the system of inequalities: x - 2y > -16 3x + 4y < 20 (8, 3) (-2, 7) (-4, -6) (11, -1)
one method plug the numbers and see which set of values satisfies both inequalities another more preferable method set the inequality as = solve the simultaneous eqn by substitution, elimination or graphing use the values as the limits to satisfy the inequalities find the intersection of both and that will be the solution to solve by substitution using the first eqn let x = -16 +2y substitute in the 2nd inequality and solve 3x + 4y < 20 3(-16 +2y) <20 substitute this y value and find x to solve by elimination set = 0 multiply the 1st eqn by 2 and add to the 2nd add, group like terms, simplify, solve then substitute satisfy the inequality and find the intersection to solve by graphing rewrite each in the form y as a function of x set up values of x and find the corresponding value of y then plot the points and draw the lines shade the section that satisfies the inequality the solution is the section that is double-shaded. finding the
the 1st method is fast in an exam , the answer is right there also note that if the values do not work for one system automatically go to the next the 2nd approach will always work. once you know how to do it and which method you prefer it's just as easy
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