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differentiate
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y= 3e^x + (4/\[\sqrt[3]{x}\]
its 4/ cube root of x
and e is not alphabet e the math e thingy lol
like this ? \(\large y=3e^x + \sqrt[4]{x}\)
yes but 3 instead of 4 in x part
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3*e^x + 1/3 x ^(-2/3)
ohk \(\large y=3e^x + \sqrt[3]{x} \) rewrite it as \(\large y=3e^x + x^{\frac{1}{3}} \)
:)
so just then just bring down and subtract with 1 the power
thank you!!
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i just like to answer before ikram to piss her off :)
LMFAO!! i see that hhahahaahahha
yep :D Parth
Dan i cant see you :P
thats so funny!!
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have a good day :P
THANK YOU GUYS!! really thank you
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