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Mathematics 10 Online
OpenStudy (anonymous):

I have a final 2mor with factoring and i was wondering if i can do anything besides factoring so it can b easier....they are multiple choices questions...

OpenStudy (anonymous):

OpenStudy (anonymous):

like those..is there anyway i could get away from factoring becuz i am horrible at it

OpenStudy (vishweshshrimali5):

First of all if, they are questions like as given in the attachment, then, you can just simplify them or try putting x = 1, 0 or -1 in question and find out the value and then put the same value of x in the options and see which one gives the same answer.

OpenStudy (vishweshshrimali5):

Let me give you an example.

OpenStudy (anonymous):

ok thanks!

OpenStudy (vishweshshrimali5):

See: consider the question 7:

OpenStudy (vishweshshrimali5):

simplify 6y^2(3y^2 - 1) ? First put y = 0 in this and tell me what will you get ?

OpenStudy (vishweshshrimali5):

@dbaseball you there ?

OpenStudy (anonymous):

yes....so it would b 18y^4-6y^2

OpenStudy (anonymous):

then you would do =0?

OpenStudy (vishweshshrimali5):

See, first of all tell me can you solve the questions given in the attachment easily ?

OpenStudy (anonymous):

i dont think so.. at least not for me

OpenStudy (vishweshshrimali5):

Its ok

OpenStudy (vishweshshrimali5):

Then follow the steps as I say: (1) See the expression in question. (2) Put, y or x or whatever variable they have used = 0 and find out the value of the expression given in the question. For example in Q.7. if I put, y = 0 in 6y^2(3y^2 - 1) what will be the value I obtain ?

OpenStudy (anonymous):

woud it b 17..idk i am really confused

OpenStudy (vishweshshrimali5):

No it wouldn't be 17. What I am asking you to do is that in place of y write 0. Can you do this ?

OpenStudy (anonymous):

say what?? lol can you draw this

OpenStudy (vishweshshrimali5):

For example, I was given \[\large{6y^2 (3y^2 - 1)}\] Now, I am writing 0 in place of y; \[\large{6*(0)^2(3*(0)^2 - 1)}\] Did you get this ?

OpenStudy (anonymous):

yup but then i got a single answer

OpenStudy (vishweshshrimali5):

Yeah what was that answer ?

OpenStudy (anonymous):

12?

OpenStudy (vishweshshrimali5):

No

OpenStudy (vishweshshrimali5):

What is 0 * any number ?

OpenStudy (anonymous):

0

OpenStudy (vishweshshrimali5):

Good. What is 0^2?

OpenStudy (anonymous):

0

OpenStudy (vishweshshrimali5):

Very good!

OpenStudy (vishweshshrimali5):

Now, see: \[\large{6*(0)^2 (3*(0)^2 - 1)}\] \[\large{= 6 * 0 * (3* 0 -1)}\] \[\large{= 0}\] Do you get this ?

OpenStudy (anonymous):

yes

OpenStudy (vishweshshrimali5):

Very good

OpenStudy (vishweshshrimali5):

So, what I did was in the expression given in the question (for example 6y^2(3y^2 - 1)), I just wrote 0 in place of y and then solved and evaluated the answer. Ok ?

OpenStudy (anonymous):

yes so whats next??

OpenStudy (vishweshshrimali5):

Now, what you are going to do is that: (1) In each option , put 0 in place of y and then solve it. And then tell me the values of each option.

OpenStudy (vishweshshrimali5):

For example in option a.: \[\large{18*y^4 - 6*y^2}\] In place of y write 0 \[\large{18*(0)^4 - 6*(0)^2}\] Now solve this. What will you get ?

OpenStudy (anonymous):

didnt we just d that and it would equal 0

OpenStudy (vishweshshrimali5):

Yes very good you would get 0. So, value for option a when y = 0 is 0. Now, what of option b ?

OpenStudy (anonymous):

whats option b?

OpenStudy (vishweshshrimali5):

9y^4 - 6y Put y = 0 and then solve it

OpenStudy (anonymous):

its 0

OpenStudy (vishweshshrimali5):

Very very good. What about option c? 18y^4 - 1

OpenStudy (anonymous):

-1

OpenStudy (vishweshshrimali5):

Very good. What about option d? 18y^3 - 6y^2

OpenStudy (anonymous):

0

OpenStudy (vishweshshrimali5):

Very very nice.

OpenStudy (vishweshshrimali5):

Now we are going to do calculations fast , very fast. So get ready! Ok ?

OpenStudy (anonymous):

ok

OpenStudy (vishweshshrimali5):

Very good.

OpenStudy (vishweshshrimali5):

In the Q.8. we have: Simplify (4p-3)^2 : (a) 16p^2 - 6p + 9 (b) 16p^2 - 12p + 9 (c) 16p^2 - 24p + 9 (d) 16p^2 - 9 Now, as we did in Q.7. (that is we put y = 0 and then solved), we are going to do the same here. Put p = 0 and then solve: (1) First solve the expression in question : (4p-3)^2 (2) then solve each expression in each option one by one

OpenStudy (vishweshshrimali5):

Can you do this ?

OpenStudy (anonymous):

yes i get that step so how do you get the answer...i understand u plug in 0 for every option

OpenStudy (vishweshshrimali5):

yes very good

OpenStudy (vishweshshrimali5):

Then you just solve it. For example , see the question: (4p-3)^2 = (4*0 - 3)^2 = (-3)^2 = 9

OpenStudy (anonymous):

and the answer is whatever is true?

OpenStudy (vishweshshrimali5):

No forget about the answer now. Just find out the values.

OpenStudy (anonymous):

ok 1) 9 2) 9 3) 9 4) -9

OpenStudy (vishweshshrimali5):

Great work

OpenStudy (vishweshshrimali5):

Now, what if I instead of asking you to put 0, I asked you to put 1.Can you calculate the values then ?

OpenStudy (anonymous):

put what?

OpenStudy (anonymous):

o 1 woops ok

OpenStudy (vishweshshrimali5):

Yes 1. For example, lets move back to Q.7. in the question: 6y^2(3y^2 - 1) put y = 1 and then find the value.

OpenStudy (anonymous):

it would b 12

OpenStudy (vishweshshrimali5):

Great

OpenStudy (vishweshshrimali5):

Now, can you calculate the values of options when y = 1 (in Q.7) ?

OpenStudy (anonymous):

ok 1) 12 2) 3 3) 17 4) 12

OpenStudy (vishweshshrimali5):

Great

OpenStudy (vishweshshrimali5):

Now, lets see how we can find out the correct answer by all this work

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

??

OpenStudy (vishweshshrimali5):

Pay very close attention: (1) Put, y = 0 in question and the options and calculate the values.

OpenStudy (vishweshshrimali5):

(2) Then, if the values obtained from the question and the option match then that option is a POSSIBLE correct answer.

OpenStudy (anonymous):

ok which question do u want me to do

OpenStudy (vishweshshrimali5):

(1) In Q.10. put x = 0 in question and options and then tell me which options are the possible correct answers.

OpenStudy (anonymous):

ok the question is narrowed down to (-2) and (2) do i just multiply them

OpenStudy (vishweshshrimali5):

Yes

OpenStudy (anonymous):

ok so the question= -4 and choices a,b and d all equal -4 but c which equals 4

OpenStudy (vishweshshrimali5):

Very good! So possible correct answers are ?

OpenStudy (anonymous):

abd

OpenStudy (vishweshshrimali5):

Very good

OpenStudy (vishweshshrimali5):

Now, (1) Put, x = 1 in possible correct options and the question

OpenStudy (anonymous):

ITS A

OpenStudy (vishweshshrimali5):

Similarly this time also if the values match, then select only those options and reject the other options.

OpenStudy (vishweshshrimali5):

Brilliant work

OpenStudy (anonymous):

thanksss soo much..just one last question...can't i just start at y=1??

OpenStudy (vishweshshrimali5):

Yeah sure

OpenStudy (vishweshshrimali5):

Remember this: You can start by putting any value of the variable and then keep on narrowing down the possible correct answers untill you have only one left.

OpenStudy (vishweshshrimali5):

Now, can you solve Q. 9 ?

OpenStudy (anonymous):

yes

OpenStudy (vishweshshrimali5):

Good go on.

OpenStudy (vishweshshrimali5):

Tell me the answer.

OpenStudy (anonymous):

it would b C

OpenStudy (vishweshshrimali5):

Brilliant

OpenStudy (vishweshshrimali5):

You did it perfectly right. Now, solve 7 and 8 also .

OpenStudy (anonymous):

omg ur a live saver...thanks again

OpenStudy (vishweshshrimali5):

Hey, do not mention it. It was my pleasure to help you.

OpenStudy (anonymous):

7=a 8=c

OpenStudy (vishweshshrimali5):

Perfect answer.

OpenStudy (vishweshshrimali5):

You really got it right. Very good work.

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