Question

Find equations of the tangent line and normal line to the curve at the given point

y=x^4+2e^x, (0,2)

Answer 1

was just about to tag you ! haha

Answer 2

okk :D
can u find the slope of the tangent for a given curve at spisific point ?

Answer 3

difference quotient formula here i am guessing

Answer 4

well , mmm
here is the steps :-
1_ find the derivative of the curve
2_apply the point u have to give the slop

Answer 5

so first find y'
and the slope would be y'(0)

Answer 6

normal line = perpendicular to the tangent at that point

Answer 7

ummmmm kinda lost cause my professor never explain pellet and he just copies off the book so i am just trying to learn here.

Answer 8

the derivative of a function evaulated at a point gives you the tangent by definition of the derivative
from first principles

Answer 9

ic.. can u find y' ?

Answer 10

dy/dx = lim as h--->0 of (f(x+h)-f(x))/h

Answer 11

this is the slope of a line evaluated using "2 points", as the distance between the points goes to zero

Answer 12

right then use y2-y1/x2-x1

Answer 13

after i get the points

Answer 14

no use derivate defintion

Answer 15

oh the lim h----> 0 f(x+h) thingy

Answer 16

thats just part of the first principle stuff, that is what a derivative is