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Mathematics 21 Online
OpenStudy (gazela1997):

How do you know if a parabola is showing the maximum or minimum value?

OpenStudy (gazela1997):

like in the equation.

OpenStudy (anonymous):

Suppose you start with a parabola in standard form: \[y=ax^2+bx+c\] Completing the square, you can write it in vertex form: \[y=a(x-h)^2+k\] where \((h,k)\) is the vertex. The sign of \(a\) determines if the vertex is a minimum or maximum. If \(a>0\), then the parabola "opens upward," so the vertex is a minimum. If \(a<0\), then the parabola "opens downward," so the vertex is a maximum.

OpenStudy (gazela1997):

heh thats weird because i got a question where to find the minimum but when I drew it, it was opening up

OpenStudy (gazela1997):

\[y=3(x-16)^{2}+246\]

OpenStudy (gazela1997):

but the questions is asking to find the minimum value. How do I do that?

OpenStudy (anonymous):

Since \(a=3>0\), the parabola opens upward, so the vertex is the minimum. Find the vertex and you'll have your answer.

OpenStudy (gazela1997):

so the vertex is (16,246)?

OpenStudy (anonymous):

Right.

OpenStudy (gazela1997):

that opening downward tho

OpenStudy (anonymous):

Check the plot: http://www.wolframalpha.com/input/?i=3%28x-16%29%5E2%2B246 That's what I mean by opening upward. Maybe you have a different interpretation

OpenStudy (gazela1997):

nope

OpenStudy (gazela1997):

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