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Mathematics 24 Online
OpenStudy (anonymous):

Find the equation of the circle that has a diameter with endpoints located at

OpenStudy (anonymous):

(-5,-3) and (-11,-3)

OpenStudy (vishweshshrimali5):

See: centre of the circle would be the midpoint of the endpoints of the diameter. Right ?

OpenStudy (vishweshshrimali5):

|dw:1402982345617:dw|

OpenStudy (vishweshshrimali5):

So, can you calculate the mid point of given points @ltp1212 ?

OpenStudy (anonymous):

-8,-3

OpenStudy (vishweshshrimali5):

Very good. So that is your centre.

OpenStudy (vishweshshrimali5):

Now, find out the distance between the given points, that would be the length of the diameter

OpenStudy (vishweshshrimali5):

You can even use the direct formula.

OpenStudy (anonymous):

6?

OpenStudy (vishweshshrimali5):

But I would suggest you to stick to the basic method.

OpenStudy (anonymous):

is it 6?

OpenStudy (vishweshshrimali5):

yes

OpenStudy (vishweshshrimali5):

So, radius = diameter /2 = 3 units

OpenStudy (vishweshshrimali5):

Now you have the centre's coordinates and radius' length. Can you find the eq. of circle now ?

OpenStudy (anonymous):

is it \[(x+8)^2+(y+3)^2=9\]

OpenStudy (vishweshshrimali5):

Yeah

OpenStudy (anonymous):

@vishweshshrimali5 thanks

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