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Calculus1 15 Online
OpenStudy (dls):

Integrate

OpenStudy (dls):

\[\Huge \int\limits\limits_0^{2\pi} e^{\cos \theta} \cos (\sin \theta) d \theta\]

ganeshie8 (ganeshie8):

@dan815

OpenStudy (dan815):

i want to complexify

OpenStudy (dls):

go ahead

OpenStudy (dan815):

integral of e^cos(theta)*e^(isintheta) integral e^(costheta+isintheta) integrate and take real part?

OpenStudy (dls):

what just happened? where did cos(sin theta) go?

OpenStudy (dan815):

i complexified it

OpenStudy (dls):

how do we complexify?

ganeshie8 (ganeshie8):

e^(e^itheta) :/

OpenStudy (dan815):

e^(isintheta) = cos(sintheta) + isin(sintheta)

OpenStudy (dls):

ohh i see :)

OpenStudy (dan815):

so we get e^(cos x+ i sin x) * (-sinx+i cos x) take the real part of that and then evaluate the bounds

ganeshie8 (ganeshie8):

dan \(\large \int e^{\cos x} dx \ne e^{\cos x} (-\sin x )\) right ?

OpenStudy (dan815):

yeah that statement is right

OpenStudy (dan815):

true xD

OpenStudy (dan815):

we shud make it into another complex

OpenStudy (dan815):

e^(costheta+isintheta) = e^(e^itheta)

ganeshie8 (ganeshie8):

yeah but the indefinite integral doesn't seem to evaluate to known functions http://www.wolframalpha.com/input/?i=%5Cint+e%5E%28cos+%5Ctheta%29cos%28%5Csin+%5Ctheta%29

OpenStudy (dan815):

apparently it evaluates to 2pi that integral :O, but that is with the unreal part

OpenStudy (dan815):

what does this become in taylor expansion?

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