In △PQR, find the measure of ∡P (angle P) (picture below) A. 30.4° B. 35.9° C. 59.6°
try
have you learned about sine, cosine and tangent?
Yes, but I tend to use them incorrectly -_-
okay, that means you just need to re-read briefly and try to comprehend what is going on by focusing on the vocabulary what adjacent, hypotenuse and opposite side meant
^Thank you, the 33.8 is the adjacent and the 57.6 is the hypotenuse ; so PQ is the opposite?
|dw:1403038352913:dw| recall your SOH CAH TOA \(\bf sin(\theta)=\cfrac{opposite\ side}{hypotenuse}\quad \textit{now, taking }sin^{-1}\textit{ to both sides} \\ \quad \\ sin^{-1}[sin(\theta)]=sin^{-1}\left(\cfrac{opposite\ side}{hypotenuse}\right)\implies \theta=sin^{-1}\left(\cfrac{opposite\ side}{hypotenuse}\right) \)
opposite of what?
the terms ADJACENT and OPPOSITE have to refer to one of the angles other than the 90 degree one
so when we say ADJACENT SIDE it means |dw:1403038045733:dw|
adjacent = "next to"
|dw:1403038197983:dw|
notice if you rotate the triangle and kept the reference angle the same, which is x in this case, the sides maintain their names
I need clarity, I keep getting everything opposite from you ..
pq=adjacent?
I am using a different drawing and point reference
don't focus on your problem for now, just focus on understanding the parts of a right triangle
^Yes but since the triangle is rotated differently, it is confusing me; I'm basing all my responses off the website you gave me..
|dw:1403038360119:dw|
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