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I need help finding the vertical asymptotes of Y=(x^2-5x+4)/(x^4-1) Is the answer Y= - oo ?
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no, a vertical asymptote is a value of x for which the function is not defined.
spose we have a rational function:\[\frac{n(x)}{d(x)}\] for some x=c if d(c)=n(c)=0, then we have a hole. if d(c) = 0, and n(c) does not equal 0, then we have a vertical asymptote at x=c
Thanks! But is the right answer for the question is x= not defined?
x is defined ... the issue is more of when the rational function is not defined. that is usually when when d(x) ... the denoninator... is equal to zero.
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