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(a+b)^6
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solve as formula
using the binomial theorem: \[a^6+6a^5b+15a^4b^2+20a^3b^3+15a^2b^4+6ab^5+b^6\]
you can read about that theorem on wikipedia, it's very simple after you construct pascal's triangle
\(6ab^5 + 15a^2b^4 + 20a^3b^3 + 15a^4b^2 + 6a^5b + a^6 + b^6\) This is your final answer.
as per pyramid rule \[a^{6}+6a ^{5}b+15a^4b^2+20a^3b^3+15a^2b^4+6a b^5+b^6
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iGreen u r wrong constant witn variable powers r not currect
sorry its right but not in sequence
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