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integrate ( 2x*pi ) cos( [pi/2] x^2 ) Medal for showing steps how to integrate! I know this answer is 2pi (1/pi) sin( [pi/2]x^2 ), but I don't know how? Please help! Thank you :)
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2*sin(x^2*pi/2)
Use U-substitution. Let \(u = \dfrac{\pi}{2}x^2\), so \(du = \pi x ~dx \rightarrow 2du = 2\pi x ~dx\)
After this substitution, integral should be easy. This helps? @student1988
Thanks, I was trying integration but parts and couldn't come up with anything. But with U sub this is really easy. Thanks! :)
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