Question

integrate ( 2x*pi ) cos( [pi/2] x^2 )

Medal for showing steps how to integrate!
I know this answer is 2pi (1/pi) sin( [pi/2]x^2 ), but I don't know how? Please help! Thank you :)

Answer 1

2*sin(x^2*pi/2)

Answer 2

Use U-substitution. Let \(u = \dfrac{\pi}{2}x^2\), so \(du = \pi x ~dx \rightarrow 2du = 2\pi x ~dx\)

Answer 3

After this substitution, integral should be easy.

This helps? @student1988

Answer 4

Thanks, I was trying integration but parts and couldn't come up with anything. But with U sub this is really easy. Thanks! :)

Answer 5

welcome