Question

Factor the following polynomial completely.

-x 2 y 2 + x 4 + 4y 2 - 4x 2

(x - 2)(x - 2)(x + y)(x - y)
(x + 2)(x + 2)(x + y)(x - y)
(x + 2)(x - 2)(x + y)(x - y)

Answer 1

I'm having trouble understanding you polynomial. Can you rewrite it using the equation tool?

Answer 2

too lazy to figure out how that works

Answer 3

Okay. What methods do you know of for factoring a polynomial?

Answer 4

I don't know this is algebra one work, which I haven't taken since 9th grade

Answer 5

Well seeing as how you have no idea, I would recommend doing some research.

Here is a link with a good explanation of different techniques. After you have read it, feel free to come back with any specific questions.

http://tutorial.math.lamar.edu/Classes/Alg/Factoring.aspx

HINT: Make sure you read the section on factoring by grouping.

Answer 6

How ya doin?

Answer 7

I don't know how to do this.

Answer 8

If I knew how to do this I wouldn't have dropped 200 dollars out of my own pocket just to retake the class in the summer.

Answer 9

\[-x^{2}y^{2} + x^{4} + 4y^{2} - 4x^{2}\]
=
\[-x^{2}(y^{2}-x^{2})+4(y^{2}-x^{2})\]
Do you see how I got here? I factored out a common denominator from each group.

Answer 10

Well my friend, the only person who can really be sure that you know what you're doing is yourself. You need to be able to study, research, and not become frustrated when you don't know how to solve a problem right away.

In math, stuff is hard. People just aren't good at math. It's the people who take the time to do research and work on a problem for hours that will succeed. Not those who go online to a forum and just say, "I don't know how to do this. Do it for me"

I am more than willing to help walk you through the steps, but by no means will I just give you an answer. You will learn NOTHING from that.

Answer 11

I don't care to learn math, I see it's importance in the world but by no means do I care to do it. I prefer the arts and sociology.

Answer 12

Well I'm sorry to hear that.

Be aware, this is not a site called: OpenAnswers. It's called OpenStudy. Maybe someone else will give you the answer, but not me. If you are willing to do some work, feel free to ask me again.