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3x3+6x2-16x4
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Final result : \[ \huge\ -x^2 • (16x^2 - 3x - 6)\]
@troygarcia You mean this equation: \[3x^3+6x^2-16x^4=0\]
yeah
\[-16x^4+3x^3+6x^2=-x^2(16x^2-3x-6)\] Your first solution is x=0; The second and third solution you get by solving: \[16x^2-3x-6=0=>X(2,3)=\frac{ 3\pm \sqrt{393} }{ 32 }\]
O.o?
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what?
where the answer?
The answer is formed by 3 solutions: \[S=0,\frac{ 3+\sqrt{393} }{ 32 },\frac{ 3-\sqrt{393} }{ 32 }\]
can you form it please
by three :D
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form what? i just gave you the solution
Your problem is a grade 4 equation and has 3 solutions what do you want more?
nahh,
ty,bye
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