Question

HELP PLEASE !!!!!!!!!!!!!!
Solve for x by completing the square:

a. x^2-mx-6m^2=0
b. kx^2+px+q=0

Answer 1

\[a.\ x ^{2}-mx-6m ^{2}=0\]
\[b. \ kx^{2}+px+q=0\]

Answer 2

What?

Answer 3

a) x^2-mx=6m^2....now add the square of (m/2) to both sides
x^2-mx+m^2/4=6m^2+m^2/4
(x-m/2)^2=25m^2/4
can you take it from here?

Answer 4

Guadratic formula: \(\huge \frac{ - \color{blue}{b} \pm \sqrt{\color{blue}{b^2} -\color{black}{4} \color{green}{a} \color{red}{c} }}{\color{black}{2} \color{green}{a}}\)
For Guadratic Equation \(\Large \color{green}{a} \color{black}{x^2}+\color{blue}{b} \color{black}{x}+\color{red}{c}=\color{black}{0}\)

1) \(\Large x^2-mx-6m^2=0\)
\(\huge \Rightarrow x=\frac{m\pm \sqrt{(-m)^2-4\times (-6)}}{2}=\frac{m\pm \sqrt{m^2+24}}{2}\)

2) \(\Large kx^2+px+q=0 \)
\(\huge \Rightarrow x=\frac{-p\pm \sqrt{p^2 -4kq}}{2k}\)

Answer 5

Can somebody translate it like for a year 9 student please? :-) thanks you

Answer 6

use mine its g9 friendly