Use mathematical induction to prove the statement is true for all positive integers n, or show why it is false. medal!!!!! @ganeshie8
4 ⋅ 6 + 5 ⋅ 7 + 6 ⋅ 8 + ... + 4n( 4n + 2) =4(4n+1)(8n+7)/6
@SithsAndGiggles do you know this?
@hartnn
I've done my share of induction proofs, yes. Give me a moment
please show all steps so i understand it
okay thanks(: @SithsAndGiggles
What happens when \(n=1\)?
i dont know:(
What I'm asking is, "is this true?" \[(4\cdot1)(4\cdot1+2)=\frac{4(4\cdot1)((8\cdot1)+7)}{6}\]
no it is false
Okay, so if the formula above doesn't hold for \(n=1\), then it's certainly true that it does not hold for ALL natural numbers. What does that tell you? Is the formula correct?
since it is false, it is not correct
Right. The counter-example is \(n=1\), so the statement/formula is false.
so wait since it is false all i have to do is write that it is false? it shows to prove that the statement is false... how to i do that?
nevermind, i understand(: thanks!
yw
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