Question

For the given statement Pn, write the statements P1, Pk, and Pk+1.
2 + 4 + 6 + . . . + 2n = n(n+1)
medal!
@SithsAndGiggles

Answer 1

P(1) is the expression with 1 term:
LHS: 2
RHS: 1(1+1) = 1(2) = 2

P(k) .. just replace all n's with k's:
LHS: 2 + 4 + 6 + ... + 2k
RHS: k(k+1)

P(k+1), here you find the (k+1)-th term, so:
LHS: 2+ 4 + 6 + ... + 2k + 2(k+1) = 2+ 4 + 6 + ... + 2k + (2k+2)
RHS: (k+1)[(k+1)+1] = (k+1)[k+2]

Answer 2

thanks! @kirbykirby

Answer 3

wait what do lhs and rhs mean?

Answer 4

left hand side = LHS
right hand side = RHS

I just used those terms to designate which side of the equality I was working on

Answer 5

ok i dont understand

Answer 6

is that all there is?

Answer 7

If you have the equation 3x = 2, then

LHS = 3x
RHS = 2

Answer 8

i know

Answer 9

well yes that's pretty much it!

Answer 10

okay thanks